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If 20 liters of a mixture contains 60% alcohol, how much alcohol is in the mixtu
If 20 liters of a mixture contains 60% alcohol, how much alcohol is in the mixture?
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Practice Questions
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Q1
If 20 liters of a mixture contains 60% alcohol, how much alcohol is in the mixture?
8 liters
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Alcohol = 60% of 20 liters = 0.6 * 20 = 12 liters.
Questions & Step-by-step Solutions
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Q
Q: If 20 liters of a mixture contains 60% alcohol, how much alcohol is in the mixture?
Solution:
Alcohol = 60% of 20 liters = 0.6 * 20 = 12 liters.
Steps: 5
Show Steps
Step 1: Understand that the mixture is 20 liters in total.
Step 2: Know that 60% means 60 out of every 100 parts is alcohol.
Step 3: Convert 60% to a decimal by dividing 60 by 100, which gives you 0.6.
Step 4: Multiply the total volume of the mixture (20 liters) by the decimal (0.6) to find the amount of alcohol.
Step 5: Calculate 0.6 * 20 liters, which equals 12 liters.
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