A person is standing 50 meters away from a vertical pole. If the angle of elevat

Practice Questions

Q1
A person is standing 50 meters away from a vertical pole. If the angle of elevation of the top of the pole is 60 degrees, what is the height of the pole?
  1. 25 m
  2. 30 m
  3. 35 m
  4. 40 m

Questions & Step-by-Step Solutions

A person is standing 50 meters away from a vertical pole. If the angle of elevation of the top of the pole is 60 degrees, what is the height of the pole?
  • Step 1: Understand the problem. You have a pole and a person standing 50 meters away from it.
  • Step 2: The angle of elevation to the top of the pole is given as 60 degrees.
  • Step 3: Recall the tangent function in a right triangle: tan(angle) = opposite side / adjacent side.
  • Step 4: In this case, the opposite side is the height of the pole, and the adjacent side is the distance from the person to the pole (50 meters).
  • Step 5: Write the equation using the tangent of the angle: tan(60°) = height / 50.
  • Step 6: Find the value of tan(60°). It is equal to √3.
  • Step 7: Substitute tan(60°) into the equation: √3 = height / 50.
  • Step 8: To find the height, multiply both sides of the equation by 50: height = 50 * √3.
  • Step 9: Calculate the height: height ≈ 50 * 1.732 (since √3 ≈ 1.732).
  • Step 10: The final height of the pole is approximately 86.6 meters.
  • Trigonometry – The problem involves using the tangent function to relate the angle of elevation to the height of the pole and the distance from the pole.
  • Right Triangle Properties – Understanding the relationship between the sides of a right triangle formed by the pole, the ground, and the line of sight.
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