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A jar contains 5 red, 3 green, and 2 yellow marbles. If one marble is drawn at r

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Question: A jar contains 5 red, 3 green, and 2 yellow marbles. If one marble is drawn at random, what is the probability that it is either red or green?

Options:

  1. 1/2
  2. 4/5
  3. 2/5
  4. 3/5

Correct Answer: 4/5

Solution: 

The total number of marbles is 5 + 3 + 2 = 10. The number of favorable outcomes (red or green) is 5 + 3 = 8. Thus, the probability is 8/10 = 4/5.

A jar contains 5 red, 3 green, and 2 yellow marbles. If one marble is drawn at r

Practice Questions

Q1
A jar contains 5 red, 3 green, and 2 yellow marbles. If one marble is drawn at random, what is the probability that it is either red or green?
  1. 1/2
  2. 4/5
  3. 2/5
  4. 3/5

Questions & Step-by-Step Solutions

A jar contains 5 red, 3 green, and 2 yellow marbles. If one marble is drawn at random, what is the probability that it is either red or green?
  • Step 1: Count the number of red marbles. There are 5 red marbles.
  • Step 2: Count the number of green marbles. There are 3 green marbles.
  • Step 3: Count the number of yellow marbles. There are 2 yellow marbles.
  • Step 4: Add the number of all marbles together: 5 (red) + 3 (green) + 2 (yellow) = 10 total marbles.
  • Step 5: Add the number of favorable outcomes (red or green): 5 (red) + 3 (green) = 8 favorable outcomes.
  • Step 6: Calculate the probability by dividing the number of favorable outcomes by the total number of marbles: 8 (favorable) / 10 (total) = 4/5.
  • Step 7: The final answer is that the probability of drawing a red or green marble is 4/5.
  • Probability – The likelihood of an event occurring, calculated as the number of favorable outcomes divided by the total number of possible outcomes.
  • Favorable Outcomes – The outcomes that satisfy the condition of the event we are interested in, in this case, drawing a red or green marble.
  • Total Outcomes – The total number of possible outcomes, which is the sum of all marbles in the jar.
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