A box contains 4 white and 6 black balls. If one ball is drawn at random, what i

A box contains 4 white and 6 black balls. If one ball is drawn at random, what is the probability that it is black given that it is not white?

A box contains 4 white and 6 black balls. If one ball is drawn at random, what is the probability that it is black given that it is not white?

Step 1: Identify the total number of balls in the box. There are 4 white balls and 6 black balls, so the total is 4 + 6 = 10 balls.
Step 2: Determine the condition given in the question. We need to find the probability of drawing a black ball given that the ball drawn is not white.
Step 3: Since we are only considering the balls that are not white, we only look at the black balls. There are 6 black balls.
Step 4: Count the total number of balls that are not white. Since there are 4 white balls, the remaining balls (which are not white) are the 6 black balls.
Step 5: Calculate the probability. The probability of drawing a black ball given that it is not white is the number of black balls divided by the total number of balls that are not white. This is 6 (black balls) / 6 (total not white) = 1.
Step 6: Conclude that the probability of drawing a black ball given that it is not white is 1.

Conditional Probability – The probability of an event occurring given that another event has already occurred.
Total Outcomes – Understanding the total number of possible outcomes in a probability scenario.
Favorable Outcomes – Identifying the number of outcomes that satisfy the condition of interest.