Determine the local maxima and minima of the function f(x) = x^4 - 4x^3 + 4x.

Practice Questions

Q1
Determine the local maxima and minima of the function f(x) = x^4 - 4x^3 + 4x.
  1. Maxima at (0, 0)
  2. Minima at (2, 0)
  3. Maxima at (2, 0)
  4. Minima at (0, 0)

Questions & Step-by-Step Solutions

Determine the local maxima and minima of the function f(x) = x^4 - 4x^3 + 4x.
  • Step 1: Write down the function f(x) = x^4 - 4x^3 + 4x.
  • Step 2: Find the first derivative f'(x) to determine where the function's slope is zero. The first derivative is f'(x) = 4x^3 - 12x^2 + 4.
  • Step 3: Set the first derivative equal to zero to find critical points: 4x^3 - 12x^2 + 4 = 0.
  • Step 4: Factor the equation or use the quadratic formula to solve for x. This gives us the critical points x = 0 and x = 2.
  • Step 5: Find the second derivative f''(x) to determine the concavity of the function. The second derivative is f''(x) = 12x^2 - 24x.
  • Step 6: Evaluate the second derivative at the critical points. First, calculate f''(0) = 12(0)^2 - 24(0) = 0. Then calculate f''(2) = 12(2)^2 - 24(2) = -8.
  • Step 7: Determine the nature of the critical points. Since f''(0) > 0, x = 0 is a local minimum. Since f''(2) < 0, x = 2 is a local maximum.
  • Critical Points – Finding where the first derivative is zero to identify potential local maxima and minima.
  • Second Derivative Test – Using the second derivative to determine the concavity at critical points to classify them as local maxima or minima.
  • Polynomial Functions – Understanding the behavior of polynomial functions and their derivatives.
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