If 1 mol of NaCl is dissolved in 1 kg of water, how many particles are present i

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Question: If 1 mol of NaCl is dissolved in 1 kg of water, how many particles are present in solution?

Options:

Correct Answer: 2

Solution:

NaCl dissociates into 2 ions (Na+ and Cl-), so 1 mol of NaCl produces 2 mol of particles in solution.

If 1 mol of NaCl is dissolved in 1 kg of water, how many particles are present in solution?

If 1 mol of NaCl is dissolved in 1 kg of water, how many particles are present in solution?

Step 1: Understand that 1 mol of NaCl means we have 1 mole of sodium chloride (NaCl).
Step 2: Know that when NaCl dissolves in water, it breaks apart into two different ions: sodium (Na+) and chloride (Cl-).
Step 3: Since 1 mol of NaCl produces 1 mol of Na+ ions and 1 mol of Cl- ions, we have a total of 2 moles of particles (1 mol Na+ + 1 mol Cl-).
Step 4: Remember that 1 mole of any substance contains approximately 6.022 x 10^23 particles (this number is called Avogadro's number).
Step 5: Calculate the total number of particles: 2 moles of particles x 6.022 x 10^23 particles/mole = 1.2044 x 10^24 particles.

Dissociation of Ionic Compounds – Understanding how ionic compounds like NaCl dissociate into their constituent ions in solution.
Molarity and Particle Count – Calculating the number of particles in a solution based on the number of moles of solute and its dissociation.