A 1 kg ball is thrown vertically upwards with a speed of 20 m/s. What is the max

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Question: A 1 kg ball is thrown vertically upwards with a speed of 20 m/s. What is the maximum height it reaches? (g = 10 m/s²)

Options:

Correct Answer: 30 m

Solution:

Using energy conservation: Initial K.E. = Potential Energy at max height. 0.5mv² = mgh. h = v²/(2g) = (20 m/s)² / (2 × 10 m/s²) = 20 m.

A 1 kg ball is thrown vertically upwards with a speed of 20 m/s. What is the maximum height it reaches? (g = 10 m/s²)

A 1 kg ball is thrown vertically upwards with a speed of 20 m/s. What is the maximum height it reaches? (g = 10 m/s²)

Correct Answer: 20 m

Step 1: Identify the initial speed of the ball, which is 20 m/s.
Step 2: Identify the mass of the ball, which is 1 kg (but it won't affect the height calculation).
Step 3: Identify the acceleration due to gravity, which is given as g = 10 m/s².
Step 4: Use the formula for maximum height reached when an object is thrown upwards: h = v² / (2g).
Step 5: Substitute the values into the formula: h = (20 m/s)² / (2 × 10 m/s²).
Step 6: Calculate (20 m/s)², which equals 400 m²/s².
Step 7: Calculate 2 × 10 m/s², which equals 20 m/s².
Step 8: Divide 400 m²/s² by 20 m/s² to find h: h = 400 / 20 = 20 m.
Step 9: Conclude that the maximum height the ball reaches is 20 meters.

Kinetic Energy and Potential Energy – The relationship between kinetic energy (K.E.) and gravitational potential energy (P.E.) is used to determine the maximum height reached by an object in free fall.
Conservation of Energy – The principle that energy cannot be created or destroyed, only transformed from one form to another, is applied to solve for maximum height.
Kinematic Equations – Understanding the basic kinematic equations can also help in solving problems related to motion under gravity.