If a torque of 5 Nm is applied to a rotating object with a moment of inertia of 2 kg·m², what is the angular acceleration?
Correct Answer: 2.5 rad/s²
- Step 1: Understand the formula for angular acceleration, which is α = Torque / Moment of inertia.
- Step 2: Identify the values given in the question: Torque = 5 Nm and Moment of inertia = 2 kg·m².
- Step 3: Substitute the values into the formula: α = 5 Nm / 2 kg·m².
- Step 4: Perform the division: 5 divided by 2 equals 2.5.
- Step 5: Write the final answer: The angular acceleration α is 2.5 rad/s².
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