If a torque of 5 Nm is applied to a rotating object with a moment of inertia of

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Question: If a torque of 5 Nm is applied to a rotating object with a moment of inertia of 2 kg·m², what is the angular acceleration?

Options:

Correct Answer: 2.5 rad/s²

Solution:

Angular acceleration α = Torque / Moment of inertia = 5 Nm / 2 kg·m² = 2.5 rad/s².

If a torque of 5 Nm is applied to a rotating object with a moment of inertia of 2 kg·m², what is the angular acceleration?

If a torque of 5 Nm is applied to a rotating object with a moment of inertia of 2 kg·m², what is the angular acceleration?

Correct Answer: 2.5 rad/s²

Step 1: Understand the formula for angular acceleration, which is α = Torque / Moment of inertia.
Step 2: Identify the values given in the question: Torque = 5 Nm and Moment of inertia = 2 kg·m².
Step 3: Substitute the values into the formula: α = 5 Nm / 2 kg·m².
Step 4: Perform the division: 5 divided by 2 equals 2.5.
Step 5: Write the final answer: The angular acceleration α is 2.5 rad/s².

Torque – Torque is a measure of the rotational force applied to an object, influencing its angular motion.
Moment of Inertia – Moment of inertia quantifies an object's resistance to changes in its rotational motion, depending on its mass distribution.
Angular Acceleration – Angular acceleration is the rate of change of angular velocity, indicating how quickly an object is rotating faster or slower.
Newton's Second Law for Rotation – This law states that the angular acceleration of an object is directly proportional to the net torque acting on it and inversely proportional to its moment of inertia.