A man is standing 50 meters away from a building. If the angle of elevation to the top of the building is 60 degrees, what is the height of the building?
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A man is standing 50 meters away from a building. If the angle of elevation to the top of the building is 60 degrees, what is the height of the building?
Q: A man is standing 50 meters away from a building. If the angle of elevation to the top of the building is 60 degrees, what is the height of the building?
Step 1: Understand the problem. A man is standing 50 meters away from a building and looking up at the top of the building at an angle of 60 degrees.
Step 2: Visualize the situation. Imagine a right triangle where one side is the height of the building, the other side is the distance from the man to the building (50 meters), and the angle between the ground and the line of sight to the top of the building is 60 degrees.
Step 3: Use the tangent function. In a right triangle, the tangent of an angle is equal to the opposite side (height of the building) divided by the adjacent side (distance from the man to the building).
Step 4: Write the formula. The formula is: height = distance * tan(angle). Here, distance = 50 meters and angle = 60 degrees.
Step 5: Find the value of tan(60 degrees). The value of tan(60 degrees) is √3, which is approximately 1.732.
Step 6: Substitute the values into the formula. Height = 50 * tan(60 degrees) = 50 * √3.
