An object is thrown vertically upwards with a speed of 30 m/s. How high will it

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Question: An object is thrown vertically upwards with a speed of 30 m/s. How high will it rise before coming to rest?

Options:

Correct Answer: 60 m

Solution:

Using the formula: h = (v² - u²) / (2g), where v = 0 m/s, u = 30 m/s, g = 9.8 m/s². h = (0 - 30²) / (2 * -9.8) = 45.92 m, approximately 45 m.

An object is thrown vertically upwards with a speed of 30 m/s. How high will it rise before coming to rest?

An object is thrown vertically upwards with a speed of 30 m/s. How high will it rise before coming to rest?

Step 1: Identify the initial speed (u) of the object. In this case, u = 30 m/s.
Step 2: Identify the final speed (v) of the object when it comes to rest. Here, v = 0 m/s.
Step 3: Identify the acceleration due to gravity (g). This is approximately g = 9.8 m/s², but since the object is moving upwards, we will use -g in our calculations.
Step 4: Use the formula for height (h) when an object is thrown upwards: h = (v² - u²) / (2g).
Step 5: Substitute the values into the formula: h = (0² - 30²) / (2 * -9.8).
Step 6: Calculate the value: h = (0 - 900) / (-19.6).
Step 7: Simplify the calculation: h = -900 / -19.6 = 45.92 m.
Step 8: Round the answer to the nearest whole number: approximately 45 m.

Kinematics – The question tests the understanding of kinematic equations, specifically the relationship between initial velocity, final velocity, acceleration due to gravity, and displacement.
Energy Conservation – It also touches on the concept of energy conservation, where kinetic energy is converted to potential energy at the peak of the object's trajectory.