In a Wheatstone bridge, if R1 = 2Ω, R2 = 3Ω, and R3 = 6Ω, what is the value of R

In a Wheatstone bridge, if R1 = 2Ω, R2 = 3Ω, and R3 = 6Ω, what is the value of R4 for balance?

In a Wheatstone bridge, if R1 = 2Ω, R2 = 3Ω, and R3 = 6Ω, what is the value of R4 for balance?

Correct Answer: 9Ω

Step 1: Understand the Wheatstone bridge setup, which has four resistors: R1, R2, R3, and R4.
Step 2: Identify the values of the resistors given in the question: R1 = 2Ω, R2 = 3Ω, R3 = 6Ω.
Step 3: Recall the balance condition for a Wheatstone bridge, which states that R1/R2 = R3/R4.
Step 4: Rearrange the balance condition to solve for R4: R4 = (R2 * R3) / R1.
Step 5: Substitute the values of R2, R3, and R1 into the equation: R4 = (3 * 6) / 2.
Step 6: Calculate the multiplication: 3 * 6 = 18.
Step 7: Divide the result by R1: 18 / 2 = 9.
Step 8: Conclude that the value of R4 for balance is 9Ω.

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