In a balanced Wheatstone bridge, if R1 = 10Ω, R2 = 15Ω, and R3 = 5Ω, what is the

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Question: In a balanced Wheatstone bridge, if R1 = 10Ω, R2 = 15Ω, and R3 = 5Ω, what is the value of R4?

Options:

Correct Answer: 7.5Ω

Solution:

Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (15 * 5) / 10 = 7.5Ω.

In a balanced Wheatstone bridge, if R1 = 10Ω, R2 = 15Ω, and R3 = 5Ω, what is the value of R4?

In a balanced Wheatstone bridge, if R1 = 10Ω, R2 = 15Ω, and R3 = 5Ω, what is the value of R4?

Correct Answer: 7.5Ω

Step 1: Understand that in a balanced Wheatstone bridge, the ratio of the resistances is equal. This means R1/R2 = R3/R4.
Step 2: Identify the values given in the question: R1 = 10Ω, R2 = 15Ω, and R3 = 5Ω.
Step 3: Write down the balance condition: R1/R2 = R3/R4.
Step 4: Rearrange the equation to solve for R4: R4 = (R2 * R3) / R1.
Step 5: Substitute the values into the equation: R4 = (15 * 5) / 10.
Step 6: Calculate the multiplication: 15 * 5 = 75.
Step 7: Divide the result by R1: 75 / 10 = 7.5.
Step 8: Conclude that the value of R4 is 7.5Ω.

Wheatstone Bridge Balance Condition – The Wheatstone bridge is a circuit used to measure unknown resistances by balancing two legs of a bridge circuit. The balance condition states that the ratio of the resistances in one leg is equal to the ratio in the other leg.
Ohm's Law – Ohm's Law relates voltage, current, and resistance in electrical circuits, which is fundamental in understanding how resistances interact in a Wheatstone bridge.