In a balanced Wheatstone bridge, if R1 = 10Ω, R2 = 15Ω, and R3 = 5Ω, what is the

In a balanced Wheatstone bridge, if R1 = 10Ω, R2 = 15Ω, and R3 = 5Ω, what is the value of R4?

In a balanced Wheatstone bridge, if R1 = 10Ω, R2 = 15Ω, and R3 = 5Ω, what is the value of R4?

Correct Answer: 7.5Ω

Step 1: Understand that in a balanced Wheatstone bridge, the ratio of the resistances is equal. This means R1/R2 = R3/R4.
Step 2: Identify the values given in the question: R1 = 10Ω, R2 = 15Ω, and R3 = 5Ω.
Step 3: Write down the balance condition: R1/R2 = R3/R4.
Step 4: Rearrange the equation to solve for R4: R4 = (R2 * R3) / R1.
Step 5: Substitute the values into the equation: R4 = (15 * 5) / 10.
Step 6: Calculate the multiplication: 15 * 5 = 75.
Step 7: Divide the result by R1: 75 / 10 = 7.5.
Step 8: Conclude that the value of R4 is 7.5Ω.

No concepts available.