In a series circuit, if one resistor has a resistivity of 5 Ω·m and another has

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Question: In a series circuit, if one resistor has a resistivity of 5 Ω·m and another has 10 Ω·m, what is the total resistance?

Options:

Correct Answer: 15 Ω

Solution:

In series, total resistance R_total = R1 + R2 = 5 + 10 = 15 Ω.

In a series circuit, if one resistor has a resistivity of 5 Ω·m and another has 10 Ω·m, what is the total resistance?

In a series circuit, if one resistor has a resistivity of 5 Ω·m and another has 10 Ω·m, what is the total resistance?

Correct Answer: 15 Ω

Step 1: Identify the resistances of the two resistors. The first resistor has a resistance of 5 Ω and the second resistor has a resistance of 10 Ω.
Step 2: Understand that in a series circuit, the total resistance is found by adding the resistances of all the resistors together.
Step 3: Add the resistance of the first resistor (5 Ω) to the resistance of the second resistor (10 Ω).
Step 4: Calculate the total resistance: 5 Ω + 10 Ω = 15 Ω.
Step 5: Conclude that the total resistance in the series circuit is 15 Ω.

Series Circuit Resistance – In a series circuit, the total resistance is the sum of the individual resistances.
Resistivity vs Resistance – Resistivity is a material property, while resistance is dependent on the geometry of the resistor and its resistivity.