In a circuit with a 24V battery and three resistors of 4Ω, 4Ω, and 8Ω in series,

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Question: In a circuit with a 24V battery and three resistors of 4Ω, 4Ω, and 8Ω in series, what is the voltage drop across the 8Ω resistor?

Options:

Correct Answer: 12V

Solution:

Total resistance R = 4Ω + 4Ω + 8Ω = 16Ω. Current I = V/R = 24V/16Ω = 1.5A. Voltage drop across 8Ω = I * R = 1.5A * 8Ω = 12V.

In a circuit with a 24V battery and three resistors of 4Ω, 4Ω, and 8Ω in series, what is the voltage drop across the 8Ω resistor?

In a circuit with a 24V battery and three resistors of 4Ω, 4Ω, and 8Ω in series, what is the voltage drop across the 8Ω resistor?

Correct Answer: 12V

Step 1: Identify the total resistance in the circuit. Add the resistances of all three resistors: 4Ω + 4Ω + 8Ω.
Step 2: Calculate the total resistance: 4Ω + 4Ω + 8Ω = 16Ω.
Step 3: Use Ohm's Law to find the current in the circuit. The formula is I = V/R, where V is the voltage of the battery (24V) and R is the total resistance (16Ω).
Step 4: Calculate the current: I = 24V / 16Ω = 1.5A.
Step 5: To find the voltage drop across the 8Ω resistor, use the formula: Voltage drop = Current (I) * Resistance (R).
Step 6: Calculate the voltage drop across the 8Ω resistor: Voltage drop = 1.5A * 8Ω = 12V.

Ohm's Law – The relationship between voltage (V), current (I), and resistance (R) in an electrical circuit, expressed as V = I * R.
Series Circuits – In a series circuit, the total resistance is the sum of individual resistances, and the same current flows through all components.