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If a circuit contains a 12V battery and two resistors in series of 3Ω and 9Ω, wh

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Question: If a circuit contains a 12V battery and two resistors in series of 3Ω and 9Ω, what is the current flowing through the circuit?

Options:

  1. 0.5A
  2. 1A
  3. 1.5A
  4. 2A

Correct Answer: 1A

Solution: 

Total resistance R = R1 + R2 = 3Ω + 9Ω = 12Ω. Using Ohm\'s law, I = V/R = 12V/12Ω = 1A.

If a circuit contains a 12V battery and two resistors in series of 3Ω and 9Ω, wh

Practice Questions

Q1
If a circuit contains a 12V battery and two resistors in series of 3Ω and 9Ω, what is the current flowing through the circuit?
  1. 0.5A
  2. 1A
  3. 1.5A
  4. 2A

Questions & Step-by-Step Solutions

If a circuit contains a 12V battery and two resistors in series of 3Ω and 9Ω, what is the current flowing through the circuit?
Correct Answer: 1A
  • Step 1: Identify the voltage of the battery, which is 12V.
  • Step 2: Identify the resistors in the circuit, which are 3Ω and 9Ω.
  • Step 3: Calculate the total resistance by adding the two resistors together: 3Ω + 9Ω = 12Ω.
  • Step 4: Use Ohm's law to find the current. Ohm's law states that current (I) equals voltage (V) divided by resistance (R).
  • Step 5: Substitute the values into the formula: I = 12V / 12Ω.
  • Step 6: Calculate the current: I = 1A.
  • Ohm's Law – Ohm's Law states that the current (I) through a conductor between two points is directly proportional to the voltage (V) across the two points and inversely proportional to the resistance (R) of the conductor.
  • Series Circuits – In a series circuit, the total resistance is the sum of the individual resistances, and the same current flows through all components.
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