In a circuit with a 10V battery and two resistors of 5 ohms each in series, what

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Question: In a circuit with a 10V battery and two resistors of 5 ohms each in series, what is the current flowing through the circuit?

Options:

Correct Answer: 2 A

Solution:

Total resistance R_total = 5 + 5 = 10 ohms. Current I = V/R_total = 10V / 10 ohms = 1 A.

In a circuit with a 10V battery and two resistors of 5 ohms each in series, what is the current flowing through the circuit?

In a circuit with a 10V battery and two resistors of 5 ohms each in series, what is the current flowing through the circuit?

Correct Answer: 1 A

Step 1: Identify the voltage of the battery, which is 10V.
Step 2: Identify the resistors in the circuit. There are two resistors, each with a resistance of 5 ohms.
Step 3: Calculate the total resistance in the circuit. Since the resistors are in series, add their resistances: 5 ohms + 5 ohms = 10 ohms.
Step 4: Use Ohm's Law to find the current. Ohm's Law states that current (I) equals voltage (V) divided by resistance (R).
Step 5: Substitute the values into the formula: I = 10V / 10 ohms.
Step 6: Calculate the current: 10V / 10 ohms = 1 A.

Ohm's Law – Ohm's Law states that the current (I) through a conductor between two points is directly proportional to the voltage (V) across the two points and inversely proportional to the resistance (R) of the conductor.
Series Circuits – In a series circuit, the total resistance is the sum of the individual resistances, and the same current flows through all components.