Question: What is the compound interest on $1200 for 3 years at a rate of 9% per annum?
Options:
Correct Answer: $400.00
Solution:
CI = A - P; A = P(1 + r)^n = 1200(1 + 0.09)^3 = 1200(1.295029) = $1554.03, CI = 1554.03 - 1200 = $354.03.