If 1 L of a 2 M solution is diluted to 3 L, what is the new molarity of the solu

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Question: If 1 L of a 2 M solution is diluted to 3 L, what is the new molarity of the solution?

Options:

Correct Answer: 0.67 M

Solution:

Using the dilution formula M1V1 = M2V2, we have 2 M * 1 L = M2 * 3 L, thus M2 = 2/3 = 0.67 M.

If 1 L of a 2 M solution is diluted to 3 L, what is the new molarity of the solution?

If 1 L of a 2 M solution is diluted to 3 L, what is the new molarity of the solution?

Correct Answer: 0.67 M

Step 1: Identify the initial molarity (M1) and volume (V1) of the solution. Here, M1 = 2 M and V1 = 1 L.
Step 2: Identify the final volume (V2) after dilution. Here, V2 = 3 L.
Step 3: Use the dilution formula, which is M1 * V1 = M2 * V2, where M2 is the new molarity we want to find.
Step 4: Substitute the known values into the formula: 2 M * 1 L = M2 * 3 L.
Step 5: Calculate the left side: 2 M * 1 L = 2 M.
Step 6: Set up the equation: 2 M = M2 * 3 L.
Step 7: To find M2, divide both sides by 3 L: M2 = 2 M / 3 L.
Step 8: Calculate M2: 2 / 3 = 0.67 M.
Step 9: The new molarity of the solution is 0.67 M.

Dilution of Solutions – Understanding how to calculate the new molarity of a solution after dilution using the formula M1V1 = M2V2.