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What is the osmotic pressure of a solution containing 0.5 moles of glucose in 2

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Question: What is the osmotic pressure of a solution containing 0.5 moles of glucose in 2 liters of solution? (R = 0.0821 L·atm/(K·mol), T = 298 K)

Options:

  1. 6.14 atm
  2. 12.28 atm
  3. 3.07 atm
  4. 1.54 atm

Correct Answer: 6.14 atm

Solution: 

Osmotic pressure (π) = (n/V)RT = (0.5/2) * 0.0821 * 298 = 6.14 atm.

What is the osmotic pressure of a solution containing 0.5 moles of glucose in 2

Practice Questions

Q1
What is the osmotic pressure of a solution containing 0.5 moles of glucose in 2 liters of solution? (R = 0.0821 L·atm/(K·mol), T = 298 K)
  1. 6.14 atm
  2. 12.28 atm
  3. 3.07 atm
  4. 1.54 atm

Questions & Step-by-Step Solutions

What is the osmotic pressure of a solution containing 0.5 moles of glucose in 2 liters of solution? (R = 0.0821 L·atm/(K·mol), T = 298 K)
Correct Answer: 6.14 atm
  • Step 1: Identify the formula for osmotic pressure, which is π = (n/V)RT.
  • Step 2: Determine the values needed for the formula: n (number of moles) = 0.5, V (volume in liters) = 2, R (gas constant) = 0.0821 L·atm/(K·mol), and T (temperature in Kelvin) = 298.
  • Step 3: Calculate the concentration (n/V) by dividing the number of moles (0.5) by the volume (2): 0.5 / 2 = 0.25 moles/L.
  • Step 4: Multiply the concentration (0.25) by R (0.0821) and T (298): 0.25 * 0.0821 * 298.
  • Step 5: Perform the multiplication: 0.25 * 0.0821 = 0.020525, then 0.020525 * 298 = 6.14.
  • Step 6: The final result is the osmotic pressure, which is 6.14 atm.
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