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Which of the following species exhibits sp3d hybridization?

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Question: Which of the following species exhibits sp3d hybridization?

Options:

  1. SF4
  2. XeF2
  3. NH3
  4. C2H4

Correct Answer: SF4

Solution: 

In SF4, the sulfur atom is sp3d hybridized, resulting in a seesaw molecular geometry.

Which of the following species exhibits sp3d hybridization?

Practice Questions

Q1
Which of the following species exhibits sp3d hybridization?
  1. SF4
  2. XeF2
  3. NH3
  4. C2H4

Questions & Step-by-Step Solutions

Which of the following species exhibits sp3d hybridization?
Correct Answer: SF4
  • Step 1: Understand what sp3d hybridization means. It involves one s orbital, three p orbitals, and one d orbital mixing together.
  • Step 2: Identify the central atom in the species you are examining. In this case, we are looking at SF4, where sulfur (S) is the central atom.
  • Step 3: Count the number of electron pairs around the central atom (sulfur). In SF4, sulfur has 4 bonding pairs (with fluorine) and 1 lone pair.
  • Step 4: Determine the total number of electron pairs. In SF4, there are 5 electron pairs (4 bonding + 1 lone pair).
  • Step 5: Recognize that 5 electron pairs require sp3d hybridization to accommodate them.
  • Step 6: Conclude that since sulfur in SF4 has 5 electron pairs, it is sp3d hybridized, leading to a seesaw molecular geometry.
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