How many grams of NaOH are needed to neutralize 1 mole of HCl?

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Question: How many grams of NaOH are needed to neutralize 1 mole of HCl?

Options:

Correct Answer: 58.5 g

Solution:

The reaction between NaOH and HCl is 1:1. The molar mass of NaOH is 40 g/mol, so 1 mole of NaOH is needed, which weighs 40 g.

How many grams of NaOH are needed to neutralize 1 mole of HCl?

How many grams of NaOH are needed to neutralize 1 mole of HCl?

Step 1: Understand the reaction between NaOH and HCl. They react in a 1:1 ratio, meaning 1 mole of NaOH neutralizes 1 mole of HCl.
Step 2: Identify how many moles of HCl you have. In this case, we have 1 mole of HCl.
Step 3: Since the ratio is 1:1, you will need 1 mole of NaOH to neutralize 1 mole of HCl.
Step 4: Find the molar mass of NaOH. The molar mass is 40 grams per mole.
Step 5: Calculate the mass of NaOH needed. Since you need 1 mole of NaOH, you will need 40 grams.

Stoichiometry – Understanding the mole ratio in chemical reactions, specifically the 1:1 ratio between NaOH and HCl in this neutralization reaction.
Molar Mass Calculation – Calculating the mass of a substance based on its molar mass and the number of moles.