How many moles are in 5.6 liters of an ideal gas at STP?

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Question: How many moles are in 5.6 liters of an ideal gas at STP?

Options:

Correct Answer: 0.5

Solution:

At STP, 1 mole of gas occupies 22.4 L. Therefore, number of moles = 5.6 L / 22.4 L/mole = 0.25 moles.

How many moles are in 5.6 liters of an ideal gas at STP?

How many moles are in 5.6 liters of an ideal gas at STP?

Step 1: Understand that STP stands for Standard Temperature and Pressure, where 1 mole of an ideal gas occupies 22.4 liters.
Step 2: Identify the volume of the gas you have, which is 5.6 liters.
Step 3: Use the formula to find the number of moles: Number of moles = Volume of gas (L) / Volume of 1 mole of gas at STP (L/mole).
Step 4: Plug in the values: Number of moles = 5.6 L / 22.4 L/mole.
Step 5: Calculate the result: 5.6 divided by 22.4 equals 0.25 moles.

Ideal Gas Law – Understanding the relationship between volume, moles, and conditions of temperature and pressure for gases.
Standard Temperature and Pressure (STP) – Recognizing that at STP, 1 mole of an ideal gas occupies 22.4 liters.