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What is the enthalpy change for the reaction N2(g) + 3H2(g) β†’ 2NH3(g) at standar

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Question: What is the enthalpy change for the reaction N2(g) + 3H2(g) β†’ 2NH3(g) at standard conditions?

Options:

  1. -92.4 kJ
  2. -45.9 kJ
  3. 0 kJ
  4. 0.5 kJ

Correct Answer: -92.4 kJ

Solution:

The standard enthalpy change for the formation of ammonia is -92.4 kJ.

What is the enthalpy change for the reaction N2(g) + 3H2(g) β†’ 2NH3(g) at standar

Practice Questions

Q1
What is the enthalpy change for the reaction N2(g) + 3H2(g) β†’ 2NH3(g) at standard conditions?
  1. -92.4 kJ
  2. -45.9 kJ
  3. 0 kJ
  4. 0.5 kJ

Questions & Step-by-Step Solutions

What is the enthalpy change for the reaction N2(g) + 3H2(g) β†’ 2NH3(g) at standard conditions?
Correct Answer: -92.4 kJ
  • Step 1: Identify the reaction: N2(g) + 3H2(g) β†’ 2NH3(g).
  • Step 2: Understand that this reaction is the formation of ammonia (NH3) from nitrogen (N2) and hydrogen (H2).
  • Step 3: Look up the standard enthalpy change for the formation of ammonia, which is a known value.
  • Step 4: The standard enthalpy change for the formation of 2 moles of ammonia (NH3) is -92.4 kJ.
  • Step 5: Conclude that the enthalpy change for the reaction at standard conditions is -92.4 kJ.
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