A force of 15 N is applied to move an object 3 m at an angle of 60 degrees to th

₹0.0

Question: A force of 15 N is applied to move an object 3 m at an angle of 60 degrees to the horizontal. What is the work done by the force?

Options:

Correct Answer: 30 J

Solution:

Work done = F × d × cos(θ) = 15 N × 3 m × cos(60°) = 15 N × 3 m × 0.5 = 22.5 J.

A force of 15 N is applied to move an object 3 m at an angle of 60 degrees to the horizontal. What is the work done by the force?

A force of 15 N is applied to move an object 3 m at an angle of 60 degrees to the horizontal. What is the work done by the force?

Correct Answer: 22.5 J

Step 1: Identify the force applied, which is 15 N.
Step 2: Identify the distance the object is moved, which is 3 m.
Step 3: Identify the angle of the force with respect to the horizontal, which is 60 degrees.
Step 4: Use the formula for work done: Work = Force × Distance × cos(Angle).
Step 5: Substitute the values into the formula: Work = 15 N × 3 m × cos(60°).
Step 6: Calculate cos(60°), which is 0.5.
Step 7: Substitute cos(60°) into the formula: Work = 15 N × 3 m × 0.5.
Step 8: Calculate the work done: Work = 15 × 3 × 0.5 = 22.5 J.

Work Done – Work is calculated as the product of the force applied, the distance moved in the direction of the force, and the cosine of the angle between the force and the direction of movement.
Cosine Function – Understanding how to apply the cosine function to find the effective component of the force in the direction of movement.