A spring with a spring constant of 200 N/m is compressed by 0.1 m. What is the w
Practice Questions
Q1
A spring with a spring constant of 200 N/m is compressed by 0.1 m. What is the work done in compressing the spring?
1 J
2 J
3 J
4 J
Questions & Step-by-Step Solutions
A spring with a spring constant of 200 N/m is compressed by 0.1 m. What is the work done in compressing the spring?
Correct Answer: 1 J
Step 1: Identify the spring constant (k). In this case, k = 200 N/m.
Step 2: Identify the compression distance (x). Here, x = 0.1 m.
Step 3: Use the formula for work done on a spring: Work done = 0.5 × k × x^2.
Step 4: Substitute the values into the formula: Work done = 0.5 × 200 N/m × (0.1 m)^2.
Step 5: Calculate (0.1 m)^2, which equals 0.01 m^2.
Step 6: Multiply 200 N/m by 0.01 m^2 to get 2 N·m.
Step 7: Multiply 2 N·m by 0.5 to find the work done: Work done = 1 J.
Hooke's Law and Work Done on Springs – The work done in compressing or stretching a spring is calculated using the formula W = 0.5 × k × x^2, where k is the spring constant and x is the displacement from the equilibrium position.
