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If the true value of a measurement is 50.0 cm and a student records a value of 4

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Question: If the true value of a measurement is 50.0 cm and a student records a value of 49.5 cm, what is the absolute error?

Options:

  1. 0.5 cm
  2. 0.0 cm
  3. 0.5 m
  4. 1.0 cm

Correct Answer: 0.5 cm

Solution: 

Absolute error = |True value - Measured value| = |50.0 - 49.5| = 0.5 cm.

If the true value of a measurement is 50.0 cm and a student records a value of 4

Practice Questions

Q1
If the true value of a measurement is 50.0 cm and a student records a value of 49.5 cm, what is the absolute error?
  1. 0.5 cm
  2. 0.0 cm
  3. 0.5 m
  4. 1.0 cm

Questions & Step-by-Step Solutions

If the true value of a measurement is 50.0 cm and a student records a value of 49.5 cm, what is the absolute error?
  • Step 1: Identify the true value of the measurement, which is 50.0 cm.
  • Step 2: Identify the measured value recorded by the student, which is 49.5 cm.
  • Step 3: Subtract the measured value from the true value: 50.0 cm - 49.5 cm.
  • Step 4: Calculate the absolute value of the result from Step 3: |50.0 - 49.5|.
  • Step 5: The result is 0.5 cm, which is the absolute error.
  • Absolute Error – The difference between the true value and the measured value, expressed as a positive number.
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