Question: A force of 40 N is applied at an angle of 60 degrees to the lever arm of length 2 m. What is the torque about the pivot?
Options:
Correct Answer: 34.64 Nm
Solution:
Torque (Ο) = F Γ r Γ sin(ΞΈ) = 40 N Γ 2 m Γ sin(60Β°) = 40 Γ 2 Γ (β3/2) = 40β3 Nm β 34.64 Nm.