Using Zeller's Congruence, July 4, 1776 falls on a Thursday.
Questions & Step-by-step Solutions
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Q
Q: What day of the week was July 4, 1776?
Solution: Using Zeller's Congruence, July 4, 1776 falls on a Thursday.
Steps: 7
Step 1: Identify the date you want to find the day of the week for. In this case, it is July 4, 1776.
Step 2: Use Zeller's Congruence formula, which is: h = (q + (13(m + 1)/5) + K + (K/4) + (J/4) - 2J) mod 7.
Step 3: Assign values to the variables in the formula: q = 4 (the day), m = 5 (July is the 7th month, but for Zeller's, we use 5 for July), K = 76 (the year 1776, last two digits), and J = 17 (the first two digits of the year).
Step 4: Plug the values into the formula: h = (4 + (13(5 + 1)/5) + 76 + (76/4) + (17/4) - 2*17) mod 7.
Step 5: Calculate each part of the formula step-by-step.
Step 6: After calculating, you will find the value of h. The result corresponds to a day of the week: 0 = Saturday, 1 = Sunday, 2 = Monday, 3 = Tuesday, 4 = Wednesday, 5 = Thursday, 6 = Friday.
Step 7: Determine that the result of h indicates that July 4, 1776 was a Thursday.
