In a hydrogen atom, what is the energy of the electron in the n=2 state?
Practice Questions
1 question
Q1
In a hydrogen atom, what is the energy of the electron in the n=2 state?
-3.4 eV
-13.6 eV
-1.51 eV
-0.85 eV
The energy of an electron in a hydrogen atom in the n=2 state is given by E_n = -13.6/n^2 = -13.6/4 = -3.4 eV.
Questions & Step-by-step Solutions
1 item
Q
Q: In a hydrogen atom, what is the energy of the electron in the n=2 state?
Solution: The energy of an electron in a hydrogen atom in the n=2 state is given by E_n = -13.6/n^2 = -13.6/4 = -3.4 eV.
Steps: 7
Step 1: Understand that 'n' represents the energy level of the electron in a hydrogen atom. In this case, n=2 means we are looking at the second energy level.
Step 2: Use the formula for the energy of an electron in a hydrogen atom, which is E_n = -13.6/n^2.
Step 3: Substitute the value of n into the formula. Here, n=2, so we calculate E_2 = -13.6/2^2.
Step 4: Calculate 2^2, which is 4.
Step 5: Now divide -13.6 by 4. This gives us E_2 = -13.6/4.
Step 6: Perform the division. -13.6 divided by 4 equals -3.4.
Step 7: Therefore, the energy of the electron in the n=2 state is -3.4 eV.
