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In a solenoid carrying current, what is the magnetic field inside the solenoid?

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Question: In a solenoid carrying current, what is the magnetic field inside the solenoid?

Options:

  1. Zero
  2. μ₀nI
  3. μ₀I
  4. μ₀I/(2n)

Correct Answer: μ₀nI

Solution: 

The magnetic field inside a solenoid carrying current is given by B = μ₀nI, where n is the number of turns per unit length.

In a solenoid carrying current, what is the magnetic field inside the solenoid?

Practice Questions

Q1
In a solenoid carrying current, what is the magnetic field inside the solenoid?
  1. Zero
  2. μ₀nI
  3. μ₀I
  4. μ₀I/(2n)

Questions & Step-by-Step Solutions

In a solenoid carrying current, what is the magnetic field inside the solenoid?
Correct Answer: B = μ₀nI
  • Step 1: Understand what a solenoid is. A solenoid is a coil of wire that creates a magnetic field when an electric current passes through it.
  • Step 2: Know that when current flows through the solenoid, it generates a magnetic field inside it.
  • Step 3: Learn the formula for the magnetic field inside a solenoid: B = μ₀nI.
  • Step 4: Identify the variables in the formula: B is the magnetic field, μ₀ is the permeability of free space (a constant), n is the number of turns of wire per unit length of the solenoid, and I is the current flowing through the wire.
  • Step 5: Remember that the magnetic field inside the solenoid is uniform and directed along the axis of the solenoid.
  • Magnetic Field in a Solenoid – The magnetic field inside a solenoid is uniform and directly proportional to the current and the number of turns per unit length.
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