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A 1 kg mass is attached to a spring with a spring constant of 200 N/m. What is t
A 1 kg mass is attached to a spring with a spring constant of 200 N/m. What is the force exerted by the spring when it is compressed by 0.1 m?
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Q1
A 1 kg mass is attached to a spring with a spring constant of 200 N/m. What is the force exerted by the spring when it is compressed by 0.1 m?
2 N
5 N
10 N
20 N
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Using Hooke's Law, F = kx = 200 N/m * 0.1 m = 20 N.
Questions & Step-by-step Solutions
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Q
Q: A 1 kg mass is attached to a spring with a spring constant of 200 N/m. What is the force exerted by the spring when it is compressed by 0.1 m?
Solution:
Using Hooke's Law, F = kx = 200 N/m * 0.1 m = 20 N.
Steps: 5
Show Steps
Step 1: Identify the spring constant (k). In this case, k = 200 N/m.
Step 2: Identify the amount the spring is compressed (x). Here, x = 0.1 m.
Step 3: Use Hooke's Law formula, which is F = k * x.
Step 4: Substitute the values into the formula: F = 200 N/m * 0.1 m.
Step 5: Calculate the force: F = 20 N.
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