A 1 kg mass is attached to a spring with a spring constant of 200 N/m. What is t
Practice Questions
Q1
A 1 kg mass is attached to a spring with a spring constant of 200 N/m. What is the force exerted by the spring when it is compressed by 0.1 m?
2 N
5 N
10 N
20 N
Questions & Step-by-Step Solutions
A 1 kg mass is attached to a spring with a spring constant of 200 N/m. What is the force exerted by the spring when it is compressed by 0.1 m?
Correct Answer: 20 N
Step 1: Identify the spring constant (k). In this case, k = 200 N/m.
Step 2: Identify the amount the spring is compressed (x). Here, x = 0.1 m.
Step 3: Use Hooke's Law formula, which is F = k * x.
Step 4: Substitute the values into the formula: F = 200 N/m * 0.1 m.
Step 5: Calculate the force: F = 20 N.
Hooke's Law – Hooke's Law states that the force exerted by a spring is directly proportional to the displacement (compression or extension) of the spring from its equilibrium position.
