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A particle moves in a circular path of radius 10 m with a speed of 5 m/s. What i
A particle moves in a circular path of radius 10 m with a speed of 5 m/s. What is the time period of the motion?
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Q1
A particle moves in a circular path of radius 10 m with a speed of 5 m/s. What is the time period of the motion?
2π s
4π s
10 s
20 s
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Time period T = 2πr/v = 2π(10 m) / (5 m/s) = 4π s.
Questions & Step-by-step Solutions
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Q
Q: A particle moves in a circular path of radius 10 m with a speed of 5 m/s. What is the time period of the motion?
Solution:
Time period T = 2πr/v = 2π(10 m) / (5 m/s) = 4π s.
Steps: 7
Show Steps
Step 1: Identify the radius of the circular path, which is given as 10 meters.
Step 2: Identify the speed of the particle, which is given as 5 meters per second.
Step 3: Use the formula for the time period T of circular motion, which is T = 2πr / v.
Step 4: Substitute the values into the formula: T = 2π(10 m) / (5 m/s).
Step 5: Calculate the numerator: 2π(10 m) = 20π m.
Step 6: Calculate the time period: T = 20π m / (5 m/s).
Step 7: Simplify the calculation: T = 4π seconds.
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