A particle moves in a circular path of radius 10 m with a speed of 5 m/s. What i

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Question: A particle moves in a circular path of radius 10 m with a speed of 5 m/s. What is the time period of the motion?

Options:

Correct Answer: 2π s

Solution:

Time period T = 2πr/v = 2π(10 m) / (5 m/s) = 4π s.

A particle moves in a circular path of radius 10 m with a speed of 5 m/s. What is the time period of the motion?

A particle moves in a circular path of radius 10 m with a speed of 5 m/s. What is the time period of the motion?

Correct Answer: 4π s

Step 1: Identify the radius of the circular path, which is given as 10 meters.
Step 2: Identify the speed of the particle, which is given as 5 meters per second.
Step 3: Use the formula for the time period T of circular motion, which is T = 2πr / v.
Step 4: Substitute the values into the formula: T = 2π(10 m) / (5 m/s).
Step 5: Calculate the numerator: 2π(10 m) = 20π m.
Step 6: Calculate the time period: T = 20π m / (5 m/s).
Step 7: Simplify the calculation: T = 4π seconds.

Circular Motion – The motion of a particle along a circular path, where the time period can be calculated using the radius and speed.
Time Period Calculation – The time taken for one complete revolution in circular motion, calculated using the formula T = 2πr/v.