A 10 kg object is at rest on a horizontal surface. If a force of 30 N is applied, what is the object's acceleration assuming a frictional force of 10 N?
Practice Questions
1 question
Q1
A 10 kg object is at rest on a horizontal surface. If a force of 30 N is applied, what is the object's acceleration assuming a frictional force of 10 N?
2 m/s²
3 m/s²
4 m/s²
5 m/s²
Net force = 30 N - 10 N = 20 N. Using F = ma, a = F/m = 20 N / 10 kg = 2 m/s².
Questions & Step-by-step Solutions
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Q
Q: A 10 kg object is at rest on a horizontal surface. If a force of 30 N is applied, what is the object's acceleration assuming a frictional force of 10 N?
Solution: Net force = 30 N - 10 N = 20 N. Using F = ma, a = F/m = 20 N / 10 kg = 2 m/s².
Steps: 8
Step 1: Identify the mass of the object. The mass is 10 kg.
Step 2: Identify the applied force. The applied force is 30 N.
Step 3: Identify the frictional force acting against the motion. The frictional force is 10 N.
Step 4: Calculate the net force by subtracting the frictional force from the applied force. Net force = 30 N - 10 N.
Step 5: Perform the subtraction: 30 N - 10 N = 20 N. So, the net force is 20 N.
Step 6: Use the formula for acceleration, which is a = F/m, where F is the net force and m is the mass.
Step 7: Substitute the values into the formula: a = 20 N / 10 kg.
Step 8: Perform the division: 20 N / 10 kg = 2 m/s². So, the acceleration is 2 m/s².
