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A 10 kg object is at rest on a horizontal surface. If a force of 30 N is applied

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Question: A 10 kg object is at rest on a horizontal surface. If a force of 30 N is applied, what is the object\'s acceleration assuming a frictional force of 10 N?

Options:

  1. 2 m/s²
  2. 3 m/s²
  3. 4 m/s²
  4. 5 m/s²

Correct Answer: 3 m/s²

Solution: 

Net force = 30 N - 10 N = 20 N. Using F = ma, a = F/m = 20 N / 10 kg = 2 m/s².

A 10 kg object is at rest on a horizontal surface. If a force of 30 N is applied

Practice Questions

Q1
A 10 kg object is at rest on a horizontal surface. If a force of 30 N is applied, what is the object's acceleration assuming a frictional force of 10 N?
  1. 2 m/s²
  2. 3 m/s²
  3. 4 m/s²
  4. 5 m/s²

Questions & Step-by-Step Solutions

A 10 kg object is at rest on a horizontal surface. If a force of 30 N is applied, what is the object's acceleration assuming a frictional force of 10 N?
Correct Answer: 2 m/s²
  • Step 1: Identify the mass of the object. The mass is 10 kg.
  • Step 2: Identify the applied force. The applied force is 30 N.
  • Step 3: Identify the frictional force acting against the motion. The frictional force is 10 N.
  • Step 4: Calculate the net force by subtracting the frictional force from the applied force. Net force = 30 N - 10 N.
  • Step 5: Perform the subtraction: 30 N - 10 N = 20 N. So, the net force is 20 N.
  • Step 6: Use the formula for acceleration, which is a = F/m, where F is the net force and m is the mass.
  • Step 7: Substitute the values into the formula: a = 20 N / 10 kg.
  • Step 8: Perform the division: 20 N / 10 kg = 2 m/s². So, the acceleration is 2 m/s².
  • Newton's Second Law of Motion – This law states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
  • Net Force Calculation – Understanding how to calculate the net force by subtracting frictional forces from applied forces.
  • Frictional Force – Recognizing the impact of friction on the motion of an object.
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