A ball is thrown vertically upward with an initial velocity of 20 m/s. How high

A ball is thrown vertically upward with an initial velocity of 20 m/s. How high will it rise before coming to a momentary stop? (g = 10 m/s²)

A ball is thrown vertically upward with an initial velocity of 20 m/s. How high will it rise before coming to a momentary stop? (g = 10 m/s²)

Correct Answer: 20 m

Step 1: Identify the initial velocity (u) of the ball, which is given as 20 m/s.
Step 2: Identify the final velocity (v) of the ball at the highest point, which is 0 m/s (the ball stops momentarily).
Step 3: Identify the acceleration (a) due to gravity, which is -10 m/s² (negative because it acts downward).
Step 4: Use the formula v² = u² + 2as. Substitute the values: 0 = (20)² + 2(-10)s.
Step 5: Simplify the equation: 0 = 400 - 20s.
Step 6: Rearrange the equation to solve for s: 20s = 400.
Step 7: Divide both sides by 20 to find s: s = 400 / 20.
Step 8: Calculate s: s = 20 m.

Kinematics – The question tests the understanding of kinematic equations, specifically how to apply them to calculate the maximum height of an object under uniform acceleration due to gravity.
Energy Conservation – It also touches on the concept of energy conservation, where the kinetic energy at the start is converted to potential energy at the peak height.