If 2 moles of an ideal gas at 300 K occupy a volume of 10 L, what is the pressur

₹0.0

Question: If 2 moles of an ideal gas at 300 K occupy a volume of 10 L, what is the pressure of the gas? (Use R = 0.0821 L·atm/(K·mol))

Options:

Correct Answer: 1.0 atm

Solution:

Using the Ideal Gas Law, P = nRT/V = (2 moles * 0.0821 L·atm/(K·mol) * 300 K) / 10 L = 4.926 atm.

If 2 moles of an ideal gas at 300 K occupy a volume of 10 L, what is the pressure of the gas? (Use R = 0.0821 L·atm/(K·mol))

If 2 moles of an ideal gas at 300 K occupy a volume of 10 L, what is the pressure of the gas? (Use R = 0.0821 L·atm/(K·mol))

Correct Answer: 4.926 atm

Step 1: Identify the variables needed for the Ideal Gas Law equation, which is P = nRT/V.
Step 2: Determine the values for each variable: n (number of moles) = 2 moles, R (ideal gas constant) = 0.0821 L·atm/(K·mol), T (temperature) = 300 K, and V (volume) = 10 L.
Step 3: Plug the values into the Ideal Gas Law equation: P = (2 moles * 0.0821 L·atm/(K·mol) * 300 K) / 10 L.
Step 4: Calculate the numerator: 2 * 0.0821 * 300 = 49.26.
Step 5: Divide the result from Step 4 by the volume: 49.26 / 10 = 4.926.
Step 6: The pressure of the gas is 4.926 atm.

Ideal Gas Law – The relationship between pressure, volume, temperature, and number of moles of an ideal gas, expressed as PV = nRT.