If 2 moles of an ideal gas at 300 K occupy a volume of 10 L, what is the pressure of the gas? (Use R = 0.0821 L·atm/(K·mol))
Practice Questions
1 question
Q1
If 2 moles of an ideal gas at 300 K occupy a volume of 10 L, what is the pressure of the gas? (Use R = 0.0821 L·atm/(K·mol))
0.5 atm
1.0 atm
2.0 atm
3.0 atm
Using the Ideal Gas Law, P = nRT/V = (2 moles * 0.0821 L·atm/(K·mol) * 300 K) / 10 L = 4.926 atm.
Questions & Step-by-step Solutions
1 item
Q
Q: If 2 moles of an ideal gas at 300 K occupy a volume of 10 L, what is the pressure of the gas? (Use R = 0.0821 L·atm/(K·mol))
Solution: Using the Ideal Gas Law, P = nRT/V = (2 moles * 0.0821 L·atm/(K·mol) * 300 K) / 10 L = 4.926 atm.
Steps: 6
Step 1: Identify the variables needed for the Ideal Gas Law equation, which is P = nRT/V.
Step 2: Determine the values for each variable: n (number of moles) = 2 moles, R (ideal gas constant) = 0.0821 L·atm/(K·mol), T (temperature) = 300 K, and V (volume) = 10 L.
Step 3: Plug the values into the Ideal Gas Law equation: P = (2 moles * 0.0821 L·atm/(K·mol) * 300 K) / 10 L.
