A ball is thrown upwards with a speed of 20 m/s. How long will it take to reach

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Question: A ball is thrown upwards with a speed of 20 m/s. How long will it take to reach the maximum height?

Options:

Correct Answer: 2 s

Solution:

Time to reach maximum height (t) = u/g = 20/9.8 ≈ 2.04 s.

A ball is thrown upwards with a speed of 20 m/s. How long will it take to reach the maximum height?

A ball is thrown upwards with a speed of 20 m/s. How long will it take to reach the maximum height?

Step 1: Understand that when a ball is thrown upwards, it will eventually stop rising and reach its maximum height before falling back down.
Step 2: Know that the initial speed (u) of the ball is 20 m/s.
Step 3: Recognize that the acceleration due to gravity (g) is approximately 9.8 m/s², and it acts downwards.
Step 4: To find the time (t) it takes to reach the maximum height, use the formula: t = u / g.
Step 5: Substitute the values into the formula: t = 20 m/s / 9.8 m/s².
Step 6: Calculate the result: t ≈ 2.04 seconds.

Kinematics – The study of motion, specifically how objects move under the influence of forces.
Projectile Motion – The motion of an object thrown into the air, subject to gravitational acceleration.
Time of Flight – The time taken for an object to reach its maximum height when thrown vertically.