A projectile is launched with a speed of 50 m/s at an angle of 60 degrees. What

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Question: A projectile is launched with a speed of 50 m/s at an angle of 60 degrees. What is the horizontal component of its velocity?

Options:

Correct Answer: 43.3 m/s

Solution:

Horizontal component (v_x) = v * cos(θ) = 50 * 0.5 = 43.3 m/s.

A projectile is launched with a speed of 50 m/s at an angle of 60 degrees. What is the horizontal component of its velocity?

A projectile is launched with a speed of 50 m/s at an angle of 60 degrees. What is the horizontal component of its velocity?

Step 1: Identify the speed of the projectile, which is given as 50 m/s.
Step 2: Identify the angle of launch, which is given as 60 degrees.
Step 3: Use the formula to find the horizontal component of velocity: v_x = v * cos(θ).
Step 4: Calculate cos(60 degrees). The value of cos(60 degrees) is 0.5.
Step 5: Substitute the values into the formula: v_x = 50 m/s * 0.5.
Step 6: Perform the multiplication: 50 * 0.5 = 25 m/s.
Step 7: The horizontal component of the velocity is 25 m/s.

Projectile Motion – Understanding how to resolve the velocity of a projectile into horizontal and vertical components using trigonometric functions.
Trigonometric Functions – Applying cosine to find the horizontal component of velocity based on the launch angle.