What is the electric field due to a point charge of +5μC at a distance of 0.1 m?

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Q: What is the electric field due to a point charge of +5μC at a distance of 0.1 m?

Solution: Electric field E = k * |q| / r² = (9 × 10^9 N m²/C²) * (5 × 10^-6 C) / (0.1 m)² = 4500 N/C.

Steps: 9

Step 1: Identify the values given in the problem. We have a point charge (q) of +5μC and a distance (r) of 0.1 m.
Step 2: Convert the charge from microcoulombs to coulombs. +5μC = 5 × 10^-6 C.
Step 3: Use the formula for electric field (E) due to a point charge: E = k * |q| / r², where k is the electrostatic constant (approximately 9 × 10^9 N m²/C²).
Step 4: Substitute the values into the formula: E = (9 × 10^9 N m²/C²) * (5 × 10^-6 C) / (0.1 m)².
Step 5: Calculate the denominator: (0.1 m)² = 0.01 m².
Step 6: Now calculate the electric field: E = (9 × 10^9) * (5 × 10^-6) / 0.01.
Step 7: Perform the multiplication: (9 × 10^9) * (5 × 10^-6) = 45,000.
Step 8: Finally, divide by 0.01: 45,000 / 0.01 = 4,500 N/C.
Step 9: Therefore, the electric field due to the point charge at the given distance is 4500 N/C.