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What is the potential difference between two points A and B in an electric field
What is the potential difference between two points A and B in an electric field of 200 N/C if the distance between them is 0.5 m?
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Practice Questions
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Q1
What is the potential difference between two points A and B in an electric field of 200 N/C if the distance between them is 0.5 m?
100 V
200 V
50 V
25 V
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Potential difference V = E * d = 200 N/C * 0.5 m = 100 V.
Questions & Step-by-step Solutions
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Q
Q: What is the potential difference between two points A and B in an electric field of 200 N/C if the distance between them is 0.5 m?
Solution:
Potential difference V = E * d = 200 N/C * 0.5 m = 100 V.
Steps: 5
Show Steps
Step 1: Identify the electric field strength (E). In this case, E = 200 N/C.
Step 2: Identify the distance (d) between points A and B. Here, d = 0.5 m.
Step 3: Use the formula for potential difference (V), which is V = E * d.
Step 4: Substitute the values into the formula: V = 200 N/C * 0.5 m.
Step 5: Calculate the result: V = 100 V.
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