If the electric field at a point is 100 N/C and the charge at that point is +5μC

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Question: If the electric field at a point is 100 N/C and the charge at that point is +5μC, what is the force experienced by the charge?

Options:

Correct Answer: 0.5 N

Solution:

Force F = E * q = 100 N/C * 5 × 10^-6 C = 0.0005 N = 0.5 N.

If the electric field at a point is 100 N/C and the charge at that point is +5μC, what is the force experienced by the charge?

If the electric field at a point is 100 N/C and the charge at that point is +5μC, what is the force experienced by the charge?

Correct Answer: 0.5 N

Step 1: Identify the electric field (E) at the point, which is given as 100 N/C.
Step 2: Identify the charge (q) at that point, which is given as +5μC. Convert this to coulombs: 5μC = 5 × 10^-6 C.
Step 3: Use the formula for force (F) experienced by the charge: F = E * q.
Step 4: Substitute the values into the formula: F = 100 N/C * 5 × 10^-6 C.
Step 5: Calculate the force: F = 100 * 5 × 10^-6 = 0.0005 N.
Step 6: Convert 0.0005 N to a more understandable form: 0.0005 N = 0.5 mN (milliNewtons).

Electric Field and Force – The relationship between electric field (E), charge (q), and force (F) is given by the formula F = E * q.