In a circuit, two capacitors of capacitance 4μF and 6μF are connected in parallel. What is the total capacitance?
Practice Questions
1 question
Q1
In a circuit, two capacitors of capacitance 4μF and 6μF are connected in parallel. What is the total capacitance?
10μF
24μF
2.4μF
0.4μF
For capacitors in parallel, the total capacitance is the sum of the individual capacitances: C_total = C1 + C2 = 4μF + 6μF = 10μF.
Questions & Step-by-step Solutions
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Q
Q: In a circuit, two capacitors of capacitance 4μF and 6μF are connected in parallel. What is the total capacitance?
Solution: For capacitors in parallel, the total capacitance is the sum of the individual capacitances: C_total = C1 + C2 = 4μF + 6μF = 10μF.
Steps: 6
Step 1: Identify the capacitance values of the two capacitors. The first capacitor (C1) has a capacitance of 4μF and the second capacitor (C2) has a capacitance of 6μF.
Step 2: Understand that when capacitors are connected in parallel, the total capacitance is found by adding the individual capacitances together.
Step 3: Write the formula for total capacitance in parallel: C_total = C1 + C2.
Step 4: Substitute the values into the formula: C_total = 4μF + 6μF.
Step 5: Perform the addition: 4μF + 6μF = 10μF.
Step 6: Conclude that the total capacitance of the circuit is 10μF.
