Two capacitors, C1 = 2μF and C2 = 3μF, are connected in series. What is the equi

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Question: Two capacitors, C1 = 2μF and C2 = 3μF, are connected in series. What is the equivalent capacitance?

Options:

Correct Answer: 1.2μF

Solution:

For capacitors in series, the equivalent capacitance C_eq is given by 1/C_eq = 1/C1 + 1/C2. Thus, 1/C_eq = 1/2 + 1/3 = 5/6, so C_eq = 6/5 = 1.2μF.

Two capacitors, C1 = 2μF and C2 = 3μF, are connected in series. What is the equivalent capacitance?

Two capacitors, C1 = 2μF and C2 = 3μF, are connected in series. What is the equivalent capacitance?

Step 1: Identify the values of the capacitors. Here, C1 = 2μF and C2 = 3μF.
Step 2: Use the formula for equivalent capacitance in series, which is 1/C_eq = 1/C1 + 1/C2.
Step 3: Substitute the values into the formula: 1/C_eq = 1/2 + 1/3.
Step 4: Find a common denominator to add the fractions. The common denominator for 2 and 3 is 6.
Step 5: Rewrite the fractions: 1/2 = 3/6 and 1/3 = 2/6.
Step 6: Add the fractions: 1/C_eq = 3/6 + 2/6 = 5/6.
Step 7: To find C_eq, take the reciprocal: C_eq = 6/5.
Step 8: Convert 6/5 to a decimal or a microfarad value: C_eq = 1.2μF.

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