Two capacitors, C1 = 2μF and C2 = 3μF, are connected in series. What is the equivalent capacitance?
Practice Questions
1 question
Q1
Two capacitors, C1 = 2μF and C2 = 3μF, are connected in series. What is the equivalent capacitance?
1.2μF
5μF
6μF
0.6μF
For capacitors in series, the equivalent capacitance C_eq is given by 1/C_eq = 1/C1 + 1/C2. Thus, 1/C_eq = 1/2 + 1/3 = 5/6, so C_eq = 6/5 = 1.2μF.
Questions & Step-by-step Solutions
1 item
Q
Q: Two capacitors, C1 = 2μF and C2 = 3μF, are connected in series. What is the equivalent capacitance?
Solution: For capacitors in series, the equivalent capacitance C_eq is given by 1/C_eq = 1/C1 + 1/C2. Thus, 1/C_eq = 1/2 + 1/3 = 5/6, so C_eq = 6/5 = 1.2μF.
Steps: 8
Step 1: Identify the values of the capacitors. Here, C1 = 2μF and C2 = 3μF.
Step 2: Use the formula for equivalent capacitance in series, which is 1/C_eq = 1/C1 + 1/C2.
Step 3: Substitute the values into the formula: 1/C_eq = 1/2 + 1/3.
Step 4: Find a common denominator to add the fractions. The common denominator for 2 and 3 is 6.
Step 5: Rewrite the fractions: 1/2 = 3/6 and 1/3 = 2/6.
