What is the electric field due to a point charge of +5μC at a distance of 0.1m?
Practice Questions
1 question
Q1
What is the electric field due to a point charge of +5μC at a distance of 0.1m?
4500 N/C
5000 N/C
45000 N/C
50000 N/C
Electric field E = k * |q| / r² = (9 × 10^9 N m²/C²) * (5 × 10^-6 C) / (0.1 m)² = 45000 N/C.
Questions & Step-by-step Solutions
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Q
Q: What is the electric field due to a point charge of +5μC at a distance of 0.1m?
Solution: Electric field E = k * |q| / r² = (9 × 10^9 N m²/C²) * (5 × 10^-6 C) / (0.1 m)² = 45000 N/C.
Steps: 7
Step 1: Identify the formula for the electric field due to a point charge, which is E = k * |q| / r².
Step 2: Determine the values needed for the formula: k (Coulomb's constant) = 9 × 10^9 N m²/C², q (the charge) = +5μC = 5 × 10^-6 C, and r (the distance) = 0.1 m.
Step 3: Substitute the values into the formula: E = (9 × 10^9 N m²/C²) * (5 × 10^-6 C) / (0.1 m)².
Step 4: Calculate (0.1 m)², which is 0.01 m².
Step 5: Now calculate E = (9 × 10^9) * (5 × 10^-6) / 0.01.
Step 6: Multiply 9 × 10^9 by 5 × 10^-6 to get 45,000.
Step 7: Finally, divide 45,000 by 0.01 to get 450,000 N/C.
