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A capacitor of capacitance 10μF is charged to a potential of 100V. What is the e
A capacitor of capacitance 10μF is charged to a potential of 100V. What is the energy stored in the capacitor?
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Practice Questions
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Q1
A capacitor of capacitance 10μF is charged to a potential of 100V. What is the energy stored in the capacitor?
0.05 J
0.1 J
0.2 J
0.01 J
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Energy stored in a capacitor is given by U = 1/2 CV² = 1/2 * 10 × 10^-6 F * (100 V)² = 0.05 J.
Questions & Step-by-step Solutions
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Q
Q: A capacitor of capacitance 10μF is charged to a potential of 100V. What is the energy stored in the capacitor?
Solution:
Energy stored in a capacitor is given by U = 1/2 CV² = 1/2 * 10 × 10^-6 F * (100 V)² = 0.05 J.
Steps: 7
Show Steps
Step 1: Identify the formula for the energy stored in a capacitor, which is U = 1/2 CV².
Step 2: Identify the values needed for the formula: C (capacitance) = 10μF and V (voltage) = 100V.
Step 3: Convert the capacitance from microfarads to farads: 10μF = 10 × 10^-6 F.
Step 4: Substitute the values into the formula: U = 1/2 * (10 × 10^-6 F) * (100 V)².
Step 5: Calculate (100 V)², which is 10000 V².
Step 6: Multiply 10 × 10^-6 F by 10000 V² to get 0.1 J.
Step 7: Multiply by 1/2: U = 1/2 * 0.1 J = 0.05 J.
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