A capacitor of capacitance 10μF is charged to a potential of 100V. What is the e

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Question: A capacitor of capacitance 10μF is charged to a potential of 100V. What is the energy stored in the capacitor?

Options:

Correct Answer: 0.1 J

Solution:

Energy stored in a capacitor is given by U = 1/2 CV² = 1/2 * 10 × 10^-6 F * (100 V)² = 0.05 J.

A capacitor of capacitance 10μF is charged to a potential of 100V. What is the energy stored in the capacitor?

A capacitor of capacitance 10μF is charged to a potential of 100V. What is the energy stored in the capacitor?

Correct Answer: 0.05 J

Step 1: Identify the formula for the energy stored in a capacitor, which is U = 1/2 CV².
Step 2: Identify the values needed for the formula: C (capacitance) = 10μF and V (voltage) = 100V.
Step 3: Convert the capacitance from microfarads to farads: 10μF = 10 × 10^-6 F.
Step 4: Substitute the values into the formula: U = 1/2 * (10 × 10^-6 F) * (100 V)².
Step 5: Calculate (100 V)², which is 10000 V².
Step 6: Multiply 10 × 10^-6 F by 10000 V² to get 0.1 J.
Step 7: Multiply by 1/2: U = 1/2 * 0.1 J = 0.05 J.

Capacitance and Energy Storage – Understanding how capacitors store energy and the formula used to calculate the energy based on capacitance and voltage.