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In a circuit with a 24V battery and three resistors in series (R1 = 2Ω, R2 = 3Ω,
In a circuit with a 24V battery and three resistors in series (R1 = 2Ω, R2 = 3Ω, R3 = 5Ω), what is the voltage drop across R2?
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Q1
In a circuit with a 24V battery and three resistors in series (R1 = 2Ω, R2 = 3Ω, R3 = 5Ω), what is the voltage drop across R2?
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Total resistance R_total = R1 + R2 + R3 = 2Ω + 3Ω + 5Ω = 10Ω. Current I = V/R_total = 24V / 10Ω = 2.4A. Voltage drop across R2 = I * R2 = 2.4A * 3Ω = 7.2V.
Questions & Step-by-step Solutions
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Q: In a circuit with a 24V battery and three resistors in series (R1 = 2Ω, R2 = 3Ω, R3 = 5Ω), what is the voltage drop across R2?
Solution:
Total resistance R_total = R1 + R2 + R3 = 2Ω + 3Ω + 5Ω = 10Ω. Current I = V/R_total = 24V / 10Ω = 2.4A. Voltage drop across R2 = I * R2 = 2.4A * 3Ω = 7.2V.
Steps: 10
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Step 1: Identify the values of the resistors: R1 = 2Ω, R2 = 3Ω, R3 = 5Ω.
Step 2: Calculate the total resistance in the circuit by adding the resistances together: R_total = R1 + R2 + R3.
Step 3: Substitute the values into the equation: R_total = 2Ω + 3Ω + 5Ω.
Step 4: Perform the addition: R_total = 10Ω.
Step 5: Use Ohm's Law to find the current in the circuit: I = V / R_total, where V is the voltage of the battery (24V).
Step 6: Substitute the values into the equation: I = 24V / 10Ω.
Step 7: Perform the division to find the current: I = 2.4A.
Step 8: Calculate the voltage drop across R2 using the formula: Voltage drop = I * R2.
Step 9: Substitute the values into the equation: Voltage drop = 2.4A * 3Ω.
Step 10: Perform the multiplication to find the voltage drop: Voltage drop = 7.2V.
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