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If the current in a circuit is split into two branches with resistances R1 = 2Ω

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Question: If the current in a circuit is split into two branches with resistances R1 = 2Ω and R2 = 4Ω, what is the current through R1 if the total current is 6A?

Options:

  1. 2A
  2. 3A
  3. 4A
  4. 6A

Correct Answer: 3A

Solution:

Using the current division rule, I1 = I_total * (R2 / (R1 + R2)) = 6A * (4Ω / (2Ω + 4Ω)) = 6A * (4/6) = 4A.

If the current in a circuit is split into two branches with resistances R1 = 2Ω

Practice Questions

Q1
If the current in a circuit is split into two branches with resistances R1 = 2Ω and R2 = 4Ω, what is the current through R1 if the total current is 6A?
  1. 2A
  2. 3A
  3. 4A
  4. 6A

Questions & Step-by-Step Solutions

If the current in a circuit is split into two branches with resistances R1 = 2Ω and R2 = 4Ω, what is the current through R1 if the total current is 6A?
  • Step 1: Identify the total current in the circuit, which is given as 6A.
  • Step 2: Identify the resistances of the two branches: R1 = 2Ω and R2 = 4Ω.
  • Step 3: Use the current division rule formula: I1 = I_total * (R2 / (R1 + R2)).
  • Step 4: Substitute the values into the formula: I1 = 6A * (4Ω / (2Ω + 4Ω)).
  • Step 5: Calculate the total resistance in the denominator: 2Ω + 4Ω = 6Ω.
  • Step 6: Substitute this value back into the formula: I1 = 6A * (4Ω / 6Ω).
  • Step 7: Simplify the fraction: 4Ω / 6Ω = 2/3.
  • Step 8: Multiply the total current by the simplified fraction: I1 = 6A * (2/3) = 4A.
  • Current Division Rule – The principle that describes how current is distributed among parallel branches in a circuit based on their resistances.
  • Ohm's Law – The relationship between voltage, current, and resistance, which is fundamental in analyzing electrical circuits.
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