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What is the total current in a circuit with a 12V battery and two 4 ohm resistor
What is the total current in a circuit with a 12V battery and two 4 ohm resistors in series?
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Practice Questions
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Q1
What is the total current in a circuit with a 12V battery and two 4 ohm resistors in series?
1 A
2 A
3 A
4 A
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Total resistance R = R1 + R2 = 4 + 4 = 8 ohms. Current I = V/R = 12V / 8 ohms = 1.5 A.
Questions & Step-by-step Solutions
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Q
Q: What is the total current in a circuit with a 12V battery and two 4 ohm resistors in series?
Solution:
Total resistance R = R1 + R2 = 4 + 4 = 8 ohms. Current I = V/R = 12V / 8 ohms = 1.5 A.
Steps: 5
Show Steps
Step 1: Identify the voltage of the battery. In this case, it is 12 volts.
Step 2: Identify the resistors in the circuit. There are two resistors, each with a resistance of 4 ohms.
Step 3: Calculate the total resistance in the circuit. Since the resistors are in series, add their resistances together: 4 ohms + 4 ohms = 8 ohms.
Step 4: Use Ohm's Law to find the current. Ohm's Law states that current (I) equals voltage (V) divided by resistance (R). Here, I = 12V / 8 ohms.
Step 5: Perform the calculation: 12 divided by 8 equals 1.5. So, the current is 1.5 amperes.
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