What is the total current in a circuit with a 12V battery and two 4 ohm resistor

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Question: What is the total current in a circuit with a 12V battery and two 4 ohm resistors in series?

Options:

Correct Answer: 2 A

Solution:

Total resistance R = R1 + R2 = 4 + 4 = 8 ohms. Current I = V/R = 12V / 8 ohms = 1.5 A.

What is the total current in a circuit with a 12V battery and two 4 ohm resistors in series?

What is the total current in a circuit with a 12V battery and two 4 ohm resistors in series?

Step 1: Identify the voltage of the battery. In this case, it is 12 volts.
Step 2: Identify the resistors in the circuit. There are two resistors, each with a resistance of 4 ohms.
Step 3: Calculate the total resistance in the circuit. Since the resistors are in series, add their resistances together: 4 ohms + 4 ohms = 8 ohms.
Step 4: Use Ohm's Law to find the current. Ohm's Law states that current (I) equals voltage (V) divided by resistance (R). Here, I = 12V / 8 ohms.
Step 5: Perform the calculation: 12 divided by 8 equals 1.5. So, the current is 1.5 amperes.

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