If a 10 ohm resistor is connected to a 30V battery, what is the energy consumed

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Question: If a 10 ohm resistor is connected to a 30V battery, what is the energy consumed in 5 seconds?

Options:

Correct Answer: 75 J

Solution:

Power P = V^2 / R = (30V)^2 / 10 ohms = 90 W. Energy = Power * Time = 90 W * 5 s = 450 J.

If a 10 ohm resistor is connected to a 30V battery, what is the energy consumed in 5 seconds?

If a 10 ohm resistor is connected to a 30V battery, what is the energy consumed in 5 seconds?

Step 1: Identify the values given in the problem. We have a resistor of 10 ohms and a battery of 30 volts.
Step 2: Use the formula for power (P) which is P = V^2 / R, where V is voltage and R is resistance.
Step 3: Substitute the values into the formula: P = (30V)^2 / 10 ohms.
Step 4: Calculate (30V)^2, which is 900.
Step 5: Divide 900 by 10 ohms to find the power: 900 / 10 = 90 watts (W).
Step 6: Now, calculate the energy consumed using the formula: Energy = Power * Time.
Step 7: Substitute the power and time into the formula: Energy = 90 W * 5 seconds.
Step 8: Multiply 90 by 5 to find the energy: 90 * 5 = 450 joules (J).

Ohm's Law – The relationship between voltage (V), current (I), and resistance (R) in an electrical circuit, often expressed as V = I * R.
Power Calculation – The calculation of electrical power using the formula P = V^2 / R, which relates voltage, resistance, and power.
Energy Consumption – The calculation of energy consumed over time using the formula Energy = Power * Time.