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In a circuit with a 24V battery and a 6 ohm resistor, what is the voltage drop a
In a circuit with a 24V battery and a 6 ohm resistor, what is the voltage drop across the resistor?
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Practice Questions
1 question
Q1
In a circuit with a 24V battery and a 6 ohm resistor, what is the voltage drop across the resistor?
4 V
12 V
24 V
6 V
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Using Ohm's law, V = I * R. First, find the current I = V/R = 24V / 6 ohms = 4 A. Then, V_drop = I * R = 4 A * 6 ohms = 24 V.
Questions & Step-by-step Solutions
1 item
Q
Q: In a circuit with a 24V battery and a 6 ohm resistor, what is the voltage drop across the resistor?
Solution:
Using Ohm's law, V = I * R. First, find the current I = V/R = 24V / 6 ohms = 4 A. Then, V_drop = I * R = 4 A * 6 ohms = 24 V.
Steps: 8
Show Steps
Step 1: Identify the values given in the problem. We have a 24V battery and a 6 ohm resistor.
Step 2: Use Ohm's law formula, which is V = I * R, where V is voltage, I is current, and R is resistance.
Step 3: First, we need to find the current (I) flowing through the circuit. Use the formula I = V / R.
Step 4: Substitute the values into the formula: I = 24V / 6 ohms.
Step 5: Calculate the current: I = 4 A (amperes).
Step 6: Now, we need to find the voltage drop across the resistor using the formula V_drop = I * R.
Step 7: Substitute the values into the formula: V_drop = 4 A * 6 ohms.
Step 8: Calculate the voltage drop: V_drop = 24 V.
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