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A circuit contains a 12V battery and two resistors of 4 ohms and 8 ohms in serie
A circuit contains a 12V battery and two resistors of 4 ohms and 8 ohms in series. What is the total current in the circuit?
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A circuit contains a 12V battery and two resistors of 4 ohms and 8 ohms in series. What is the total current in the circuit?
1 A
0.5 A
2 A
3 A
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Total resistance R = R1 + R2 = 4 + 8 = 12 ohms. Current I = V/R = 12V / 12 ohms = 1 A.
Questions & Step-by-step Solutions
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Q: A circuit contains a 12V battery and two resistors of 4 ohms and 8 ohms in series. What is the total current in the circuit?
Solution:
Total resistance R = R1 + R2 = 4 + 8 = 12 ohms. Current I = V/R = 12V / 12 ohms = 1 A.
Steps: 6
Show Steps
Step 1: Identify the voltage of the battery, which is 12V.
Step 2: Identify the values of the resistors, which are 4 ohms and 8 ohms.
Step 3: Calculate the total resistance in the circuit by adding the two resistors together: 4 ohms + 8 ohms = 12 ohms.
Step 4: Use Ohm's Law to find the current. Ohm's Law states that Current (I) = Voltage (V) / Resistance (R).
Step 5: Substitute the values into the formula: I = 12V / 12 ohms.
Step 6: Calculate the current: 12V / 12 ohms = 1 A.
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